I'm thinking of a 4-letter word. If you shift each letter in my word one letter to the right (eg. "p" becomes "q" etc.) and then construct the number 2^{n1}*3^{n2}*5^{n3}*7^{n4} where n1 stands for the position in the alphabet of the 1st letter in my shifted word, n2 stands for the position in the alphabet of the 2nd letter in my shifted word etc. (the position in the alphabet of the letter "b" is 2, the position in the alphabet of the letter "f" is 6 etc.) the number you get is 480290277600 What was my original word? Note: The fundamental theorem of arithmetic says that *every* number has a *unique* factorization of the form 2^{n1}*3^{n2}*5^{n3}*7^{n4}*11^{n5}*13^{n6}*17^{n7} ... where the exponents are non-negative integers. This is called the prime factorization of the number. It would therefore behoove you to figure out the factorization of our colossal number. Lee, aka |